1. | 5
🅖
|
Male
🅜
| ENG🏴 | Pete | Redmond | 1885K |
|
1
2+2. Andrew C Wainwright 1980K | | |
2
5=5. Andrew B Mata 1881A | |
1
6+6. Gary Corcoran 1738K |
1
3=3. James Hall 1969A | |
2
4+4. Paul Butterworth 1834A | 4Tie-break: SPS:12 SOS:10 SNB:7.75 | 255275K |
2. | 5
🅖
|
Male
🅜
| ENG🏴 | Andrew C | Wainwright | 1980K |
|
2
1–1. Pete Redmond 1885K | |
1
3=3. James Hall 1969A | |
2
4+4. Paul Butterworth 1834A | | |
2
6+6. Gary Corcoran 1738K |
1
5=5. Andrew B Mata 1881A | 3Tie-break: SPS:7.5 SOS:11 SNB:4.75 | 185834J |
3. | 5
🅖
|
Male
🅜
| ENG🏴 | James | Hall | 1969A |
1
4=4. Paul Butterworth 1834A | | |
2
2=2. Andrew C Wainwright 1980K | |
1
5+5. Andrew B Mata 1881A | |
2
1=1. Pete Redmond 1885K | | | 2.5Tie-break: SPS:11 SOS:11 SNB:6.5 | 111918H |
4. | 5
🅖
|
Male
🅜
| ENG🏴 | Paul | Butterworth | 1834A |
2
3=3. James Hall 1969A | | | |
2
6+6. Gary Corcoran 1738K |
1
2–2. Andrew C Wainwright 1980K | |
2
5=5. Andrew B Mata 1881A | |
1
1–1. Pete Redmond 1885K | 2Tie-break: SPS:7.5 SOS:12 SNB:2.75 | 154114G |
5. | 5
🅖
|
Male
🅜
| ENG🏴 | Andrew B | Mata | 1881A |
| |
1
6=6. Gary Corcoran 1738K | |
1
1=1. Pete Redmond 1885K |
2
3–3. James Hall 1969A | |
1
4=4. Paul Butterworth 1834A | |
2
2=2. Andrew C Wainwright 1980K | 2Tie-break: SPS:6 SOS:12 SNB:4.75 | 115075D |
6. | 5
🅖
|
Male
🅜
| ENG🏴 | Gary | Corcoran | 1738K |
| |
2
5=5. Andrew B Mata 1881A | |
1
4–4. Paul Butterworth 1834A | |
2
1–1. Pete Redmond 1885K | |
1
2–2. Andrew C Wainwright 1980K | | 0.5Tie-break: SPS:2 SOS:11 SNB:1 | 258651E |